Jay Climbed a tree to a height of 9.25m above the ground. His dog runs away from the base of the tree at 8m/s. Find the angle of depression in degrees and minutes from Jay to his dog after 2...

Jay Climbed a tree to a height of 9.25m above the ground. His dog runs away from the base of the tree at 8m/s. Find the angle of depression in degrees and minutes from Jay to his dog after 2 seconds. 

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aruv | High School Teacher | (Level 2) Valedictorian

Posted on

Dog will mve awayfrom tree in 2 sec.= 8 x 2 =16 m

In right angle triangle ,height of the triangle = height of the tree =9.25

base of the triangle= 16 m

Since angle of depression =angle of elevation

Thus

Let angle of depression be `theta`

So

`tan(theta)=9.25/16 =.578125`

`theta=30.03^0=30^0+(.03)^0`

since

`1^0=60` min.

`.03^0=(60xx.03)=1.8` min.

Thus

angle of depression is 30 degree and 1.8 min.

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