Let quarters be represented by the variable "x".
Then dimes would be represented by 2x + 4.
The value of a quarter is 0.25 therefore, the total money for quarters can be represented by `0.25x.`
The value of a dime is 0.10 therefore the total value of dimes can be represented by `0.10(2x + 4)` .
The total can be found adding the 2 values together to equal $10.75.
`.25x + .10(2x + 4) = 10.75` Solve for x
`0.25x + 0.2x + .4 = 10.75`
`0.45x = 10.35`
`x = 23`
Therefore, there are 23 quarters and 50 dimes.
A jar contains $10.75 in dimes and quarters. The number of dimes is four more than twice the number of quarters.
Let x represent the number of quarters in the jar.
As the number of dimes is 4 more than twice the number of quarters, it can be represented by 2x + 4
Now the value of dimes is .1*(2x+4) and the value of quarters is 0.25*x
.1*(2x+4) + 0.25*x = 10.75
.2*x + .4 + .25*x = 10.75
0.45*x = 10.35
x = 23
This gives the number of quarters in the jar as 23 and the number of dimes is 50.