# A jar contains \$10.75 in dimes and quarters. If the number of dimes is four more than twice the number of quarters, determine the number of each type of coin. Let quarters be represented by the variable "x".

Then dimes would be represented by 2x + 4.

The value of a quarter is 0.25 therefore, the total money for quarters can be represented by `0.25x.`

The value of a dime is 0.10 therefore the total value of dimes can be represented...

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Let quarters be represented by the variable "x".

Then dimes would be represented by 2x + 4.

The value of a quarter is 0.25 therefore, the total money for quarters can be represented by `0.25x.`

The value of a dime is 0.10 therefore the total value of dimes can be represented by `0.10(2x + 4)` .

The total can be found adding the 2 values together to equal \$10.75.

`.25x + .10(2x + 4) = 10.75` Solve for x

`0.25x + 0.2x + .4 = 10.75`

`0.45x = 10.35`

`x = 23`

Therefore, there are 23 quarters and 50 dimes.

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