Inverse of a number: find the multiplicative inverse of the number 3 + 2i.

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The multiplicative inverse is another name for the reciprocal. Both numbers are such that, if multiplied by the given number, they result in 1. The number 1 is special with regard to the operation of multiplication because if a number is multiplied by 1, it remains the same.

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The multiplicative inverse is another name for the reciprocal. Both numbers are such that, if multiplied by the given number, they result in 1. The number 1 is special with regard to the operation of multiplication because if a number is multiplied by 1, it remains the same.

As an aside, the operation of addition has a similar such number, which is zero. Adding a zero to a number results in the same number. Additive inverse, also called opposite, is a number such that its addition to the given number results in zero.

In this case, we need to find a number which will result in 1 when multiplied by the complex number 3 + 2i. (Recall that i is the imaginary number such that i^2 = -1.) In other words, we need to find 1/(3 + 2i).

In order to perform the division by a complex number, we need to multiply both the top and bottom of the fraction by its conjugate, 3 - 2i:

1/(3 + 2i) = (3 - 2i)/[(3+2i)(3-2i)].

The product on the bottom can be simplified using the "difference of two squares" formula, (a+b)(a-b) = a^2 - b^2, and the result is

(3+2i)(3-2i) = 9-(2i)^2 = 9 - (-4) = 13.

Thus, 1/(3+2i) = (3-2i)/13 = 3/13 - (2/13)i.

The complex number 3/13 -(2/13)i is the multiplicative inverse of the number 3 + 2i.

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The multiplicative inverse of a number A is another number B which when multiplied by A gives 1.

Here we have the number 3 + 2i

Let A = 3 + 2i, we need to find B such that A*B = 1

=> B = 1/(3 + 2i)

=> B = (3 - 2i)/(3 + 2i)(3 - 2i)

=> 3 - 2i /( 9 + 4)

=> 3/13 - 2i/13

The multiplicative inverse is 3/13 - 2i/13

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