The intercepts of the line x - 8y + 4 = 0 are:

Expert Answers
justaguide eNotes educator| Certified Educator

The equation of the line x - 8y + 4 = 0 can be written in the intercept-intercept form `x/a + y/b = 1` . The x-intercept is a and the y-intercept is b.

x - 8y + 4 = 0

=> x- 8y = -4

=> `x/(-4) + y/(1/2) = 1`

The x-intercept of the line is -4 and the y-intercept is 1/2

baxthum8 eNotes educator| Certified Educator

Find the intercepts of `x - 8y + 4 = 0`

Rewrite in standard form: ax + by = c.  `x - 8y = -4`

To find x-intercept, solve by letting y = 0.

`x - 8(0) = -4`

`x = -4` The x-intercept is (-4, 0).

To find the y-intercept, solve by letting x = 0.

`0 - 8y = -4`

`-8y = -4`

`y = 1/2`

The y-intercept is (0, 1/2)

The x-intercept is:  `(-4, 0)`

The y-intercept is: `(0, 1/2)`

tonys538 | Student

The x-intercept of a line is the point where it intersects x-axis. Here, the y-coordinate is equal to 0. At the y-intercept the x-coordinate is equal to 0.

For the line x - 8y + 4 = 0:

At the x-intercept x - 8*0 + 4 = 0 or x = -4

At the y-intercept 0 - 8y + 4 = 0 or y = 1/2

The x and y intercepts of the line are -4 and 1/2 respectively