`int y^3 + 1.8y^2 - 2.4y dy` Find the general indefinite integral.

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Chapter 5, 5.4 - Problem 8 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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lemjay | High School Teacher | (Level 3) Senior Educator

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`int (y^3+1.8y^2-2.4y)dy`

To evaluate this integral, apply the formula `int x^n dx = x^(n+1)/(n+1) + C` .

`= y^4/4 + 1.8y^3/3 - 2.4y^2/2 + C`

`=0.25y^4 + 0.6y^3 - 1.2y^2 + C`

 

Therefore, ` int(y^3+1.8y^2-2.4y)dy = 0.25y^4+0.6y^3-1.2y^2 + C` .

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