`int (x + 7) dx` Find the indefinite integral.

Textbook Question

Chapter 4, 4.1 - Problem 11 - Calculus of a Single Variable (10th Edition, Ron Larson).
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sciencesolve | Teacher | (Level 3) Educator Emeritus

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You need to evaluate the indefinite integral, hence, you need to split the integral, such that:

`int (x + 7) dx = int x dx - int 7 dx`

You need to use the following formula `int x^n dx = (x^(n+1))/(n+1) + c`

Replacing 1 for n yields:

`int x^1 dx = (x^(1+1))/(1 +1) + c`

`int x^1 dx = (x^2)/2 + c`

`int (x+7) dx =(x^2)/2 + 7x + c`

Hence, evaluating the indefinite integral, yields `int (x+7) dx =(x^2)/2 + 7x + c.`

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