`int x^2/sqrt(36-x^2) dx` Find the indefinite integral
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kseddy123
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Given
`int x^2/sqrt(36-x^2) dx`
This can be solved by using the Trigonometric substitutions (Trig substitutions)
when the integral contains `sqrt(a-bx^2)` then we have to take
`x=sqrt(a/b) sin(t)` in order to solve the integral easily
so here , For
`int x^2/sqrt(36-x^2) dx`
`x` is given as
`x= sqrt(36/1) sin(t) = 6sin(t) `
=> `dx = 6 cos(t) dt`
so ,
`int x^2/sqrt(36-x^2) dx`
=`int...
(The entire section contains 213 words.)
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