`int v(v^2 + 2)^2 dv` Find the general indefinite integral.

Textbook Question

Chapter 5, 5.4 - Problem 10 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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gsarora17 | (Level 2) Associate Educator

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`intv(v^2+2)^2dv`

`=intv((v^2)^2+2v^2*2+2^2)dv`

`=intv(v^4+4v^2+4)dv`

`=int(v^5+4v^3+4v)dv`

apply the power rule,

`=v^6/6+4v^4/4+4v^2/2+C` , C is constant

`=v^6/6+v^4+2v^2+C`

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