Student Comments

aruv | Student

`int1/sqrt(z)dz=int(z)^(-1/2)dz`

`=z^(-1/2+1)/(-1/2+1)+c`

`=z^(1/2)/(1/2)+c`

`=2z^(1/2)+c`

where c is integrating constant.

Student Comments

aruv | Student

`int1/sqrt(z)dz=int(z)^(-1/2)dz`

`=z^(-1/2+1)/(-1/2+1)+c`

`=z^(1/2)/(1/2)+c`

`=2z^(1/2)+c`

where c is integrating constant.