`int_4^9 ln(y)/sqrt(y) dy` Evaluate the integral

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`int_4^9 lny/sqrty dy`

To evaluate, apply integration by parts `intudv=uv-intvdu` .

So let:

`u = ln y `    


`dv=int1/sqrty dy`

Then, differentiate u and integrate dv.

`du=1/y dy`


`v=int 1/sqrty dy = int y^(-1/2)=2y^(1/2)`

Plug-in them to the formula....

(The entire section contains 126 words.)

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