`int (1 + tan^2(x)) dx` Find the general indefinite integral.

Textbook Question

Chapter 5, 5.4 - Problem 17 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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sciencesolve | Teacher | (Level 3) Educator Emeritus

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You need to find the indefinite integral, hence, you need to remember that `1 + tan^2 x = 1/(cos^2 x) = (tan x)'.`

`int (1 + tan^2 x )dx = int (tan x)' dx = tan x + c`

Hence, evaluating the indefinite integral, yields `int (1 + tan^2 x )dx = tan x + c.`

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