`int_1^9(sqrt(x))dx` Evaluate the integral.

Textbook Question

Chapter 5, 5.3 - Problem 23 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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sciencesolve | Teacher | (Level 3) Educator Emeritus

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You need to evaluate the definite integral such that:

`int_1^9 sqrt x dx = (x^(3/2))/(3/2)|_1^9`

`int_1^9 sqrt x dx = (2/3)(9sqrt9 - 1sqrt1)`

`int_1^9 sqrt x dx = (2/3)(27-1)`

 

`int_1^9 sqrt x dx = (2/3)(26) `

`int_1^9 sqrt x dx = (52/3)`

 

Hence, evaluating the definite integral yields `int_1^9 sqrt x dx = (52/3).`

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