`int_1^9(sqrt(x))dx` Evaluate the integral.

Expert Answers
sciencesolve eNotes educator| Certified Educator

You need to evaluate the definite integral such that:

`int_1^9 sqrt x dx = (x^(3/2))/(3/2)|_1^9`

`int_1^9 sqrt x dx = (2/3)(9sqrt9 - 1sqrt1)`

`int_1^9 sqrt x dx = (2/3)(27-1)`

 

`int_1^9 sqrt x dx = (2/3)(26) `

`int_1^9 sqrt x dx = (52/3)`

 

Hence, evaluating the definite integral yields `int_1^9 sqrt x dx = (52/3).`