# `int_1^18(sqrt(3/z))dz` Evaluate the integral.

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### 1 Answer

Evaluate `int_1^18(3/z)^(1/2)dz`

`=int_1^18sqrt(3)z^(-1/2)dz`

`=sqrt(3)int_1^18z^(-1/2)dz`

Integrate the function.

`=sqrt(3)[z^(1/2)/(1/2)]=sqrt(3)[2z^(1/2)]`

Evaluate the function from 1 to 18.

`=sqrt(3)[2(18)^(1/2)-2(1)^(1/2)]`

**=11.233 **