`int_0^(sqrt(3)/2) dr/(sqrt(1 - r^2))` Evaluate the integral

Expert Answers
Borys Shumyatskiy eNotes educator| Certified Educator

Hello!

This integral is a table one, `int(dr)/(sqrt(1-r^2))=arcsin(r)+C.`

` `

Therefore the definite integral is equal to

`arcsin(sqrt(3)/2)-arcsin(0)=pi/3-0=pi/3 approx 1.047.`

=arcsin(r)+C.

Access hundreds of thousands of answers with a free trial.

Start Free Trial
Ask a Question