The integral is improper because the function under the integral is not defined at zero (see the image below).

`1/sqrt0=1/0`

`int_0^4 1/sqrt x dx=2sqrt x|_0^4=2(sqrt 4-sqrt0)=4`

**The integral converges and its value is equal to 4.**

The image below shows graph of the function and area under it representing...

## Unlock

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

The integral is improper because the function under the integral is not defined at zero (see the image below).

`1/sqrt0=1/0`

`int_0^4 1/sqrt x dx=2sqrt x|_0^4=2(sqrt 4-sqrt0)=4`

**The integral converges and its value is equal to 4.**

The image below shows graph of the function and area under it representing the value of the integral.