`int_0^2(y - 1)(2y + 1)dy` Evaluate the integral.

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lemjay eNotes educator| Certified Educator

`int_0^2 (y-1)(2y+1)dy`

Before evaluating, expand the integrand.

`=int_0^2 (2y^2+y-2y-1)dy`


Then, apply the integral formulas `int x^n dx=x^(n+1)/(n+1)` and `int cdx = cx` .


Then, plug-in the limits of  the integral to the resulting function.

`= ((2(2)^3)/3-2^2/2-2)-((2(0)^3)/3-0^2/2-0)`






Therefore, `int_0^2 (y-1)(2y+1)dy = 4/3` .

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