`int_0^1(u + 2)(u - 3)du` Evaluate the integral.

Expert Answers
gsarora17 eNotes educator| Certified Educator

`int_0^1(u+2)(u-3)du`

`=int_0^1(u^2-3u+2u-6)du`

`=int_0^1(u^2-u-6)du`

`=[u^3/3-u^2/2-6u]_0^1`

`=[1^3/3-1^2/2-6*1]-[0^3/3-0^2/2-6*0]`

`=(1/3-1/2-6)`

`=(2-3-36)/6`

=-37/6