# `int_0^1 dx/(5x-3)` Decide whether the integral is improper. Explain your reasoning

An integral is improper if we have to take limit in order to calculate it. This can happen if we have infinite values of integration or if the interval if integration contains point(s) where the function is not defined. The latter is the case here because the function we are...

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An integral is improper if we have to take limit in order to calculate it. This can happen if we have infinite values of integration or if the interval if integration contains point(s) where the function is not defined. The latter is the case here because the function we are integrating is not defined for `x=3/5` which means we would have to take limit at this point.

Therefore, the integral is improper.

The image below shows the graph of the function. Red dashed line is the vertical asymptote with equation `x=3/5.`

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