`int_0^1(cosh(t))dt` Evaluate the integral.

Textbook Question

Chapter 5, 5.3 - Problem 38 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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nees101's profile pic

nees101 | Student, Graduate | (Level 2) Adjunct Educator

Posted on

We have to evaluate the inte``gral `\int_{0}^{1}cosh(t)dt` ``

We know that the integral of cosh(t) = sinh(t) . Therefore we can write,

`\int_{0}^{1}cosh(t)dt=[sinh(t)]_{0}^{1}`

                  `=sinh(1)-sinh(0)`

                   `=sinh(1)`

                    = 1.175

scisser's profile pic

scisser | (Level 3) Honors

Posted on

The antiderivative of cosh(t)=sinh(t)

Therefore,

`int_0^1(cosh(t))dt=sinh(t)|_0^1`

Plug in the upper value and subtract the lower limit

`=sinh(1)-sinh(0)`

`=1.17`

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