`int_0^1(cosh(t))dt` Evaluate the integral.

Expert Answers
Neethu eNotes educator| Certified Educator

We have to evaluate the inte``gral `\int_{0}^{1}cosh(t)dt` ``

We know that the integral of cosh(t) = sinh(t) . Therefore we can write,




                    = 1.175

scisser | Student

The antiderivative of cosh(t)=sinh(t)



Plug in the upper value and subtract the lower limit



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