Imagine that a certain animal's fur length is determined by three genes. The genotype for long fur is AABBCC and aabbcc for short fur. A cross between long fur and short fur produces f1 offspring...
Imagine that a certain animal's fur length is determined by three genes. The genotype for long fur is AABBCC and aabbcc for short fur. A cross between long fur and short fur produces f1 offspring with medium length fur (AaBbCc). Draw a punnett square that shows a cross between two f1 offspring.
In order to draw a Punnett square showing a cross between two of the F1 generation, you will have eight different types of gene possibilities from the mother as to type of egg cell, and eight from the father for type of sperm cell. I can't draw it here due to limitations of what I can put in this answer box, but I can tell you what to put across the top of your Punnett square, and what to put down the side.
The eight possibilities of genotypes from the mother are ABC, ABc, AbC, aBC, Abc, aBc, abC, and abc. The genotypes for the father are the same. You will need a square with eight spaces across the top, and eight down the side, for 64 total possible offspring boxes for the F2 generation. There will be some duplications in the 64 boxes. For example, AbC (mother) crossed with aBC (father) will give the same genotype as aBC (mother) crossed with AbC (father). In each case, the offspring will be AaBbCC.