# A boat can travel at 20 km/h in still water and is sailing in a river with a current of 10 km/h. If the boat has fuel for 4 hours when should it turn around so that it does not run out of fuel.

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### 1 Answer

The boat can travel in still water at 20 km/h. In a river with a current of 10 km/h, its speed when sailing downstream is 30 km/h and when sailing upstream it is 10 km/h. The boat has fuel to travel for 4 hours.

The boat sails downstream initially; let the the time after which it has to turn around be T. The distance traveled by the boat sailing downstream for T hours is 30*T. It turns around and has to cover a distance of 30*T in (4 - T) hours at a speed of 10 km/h.

This gives 30*T = 10*(4 - T)

=> 30*T = 40 - 10*T

=> 40*T = 40

=> T = 1

**The boat has to turn around after 1 hour to be able to come back to base with the fuel it has.**