Hydrogen sulfide can be removed from natural gas by the reaction : 2H2S(g)+ SO2(g)<------>3S(s)+ 2H20(g)Calculate deltaGknot and K (at 298 K) for this reaction. Would this reaction be...

Hydrogen sulfide can be removed from natural gas by the reaction :

2H2S(g)+ SO2(g)<------>3S(s)+ 2H20(g)

Calculate deltaGknot and K (at 298 K) for this reaction. Would this reaction be favoured at a higher or lower temperature?

Asked on by mrbest55

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jerichorayel | College Teacher | (Level 2) Senior Educator

Posted on

To solve the` Delta G^o` of the reaction at 298K, the values for the `Delta G^o` of the species involved is necessary. For the equation:

`2H_2S(g)+ SO_2(g)<=>3 S(s)+ 2H_2O(g)`

`Delta G^o` = Sum of Delta G of products - Sum of Delta G of reactants

`Delta G^o = (2 Delta G of H_2O + 3 Delta G of S) - (2 Delta G of H_2S + Delta G of SO_2)`

`Delta G H_2O (g) ` = - 228.57 kJ/mol

`Delta G H_2S (g)` = - 33.56 kJ/mol

`Delta G S (s` ) = 0 

`Delta G SO_2 ` = -300.19 kJ/mol

By substituting the values:

`Delta G^o = (2(- 228.57)+ 3 (0)) - (2 (-33.56) + (-300.19))`

`Delta G^o = (-457.14) - ((-67.12)+ (-300.19))`

`Delta G^o = (-457.14) - (-367.31)`` `

`Delta G^o =`  -107.83 kJ


Sources:

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