The pressure applied to an enclosed liquid is transmitted undiminished to every point in the fluid and to the walls of the container. Hence we can equate the pressure produced by the force applied to the piston to the pressure due to the weight of the automobile and solve for `F` .

Express the pressure the weight of the automobile exerts on the shaft of the lift.

`P_(a u t o)=w_(a u t o)/A_(s h a f t)`

Express the pressure the force applied to the piston produces.

`P=F/A_(p i s t o n)`

We want to know how much force is need to make `P=P_( a u t o)` . Therefore,

`P=P_(a u t o)`

`F/A_(p i s t o n)=w_(a u t o)/A_(s h a f t)`

`F=w_(a u t o)*(A_(p i s t o n)/A_(s h a f t))`

`F=m_(a u t o)g*(A_(p i s t o n)/A_(sh a f t))`

`F=(1500 kg)*(9.81 m/s^2)*((1.00 cm)/(8.00 cm))^2`

`F=230 N`

**Further Reading**