How to write the quadratic x^2-14x+50 to the vertex form?
add it in the parentheses and minus it on the outside
find the square root of a and c
the x is 7 and the y is the +1 on the outside
We'll recall the vertex form of the equation of a parabola:
f(x) = a(x-h)^2 + k
"a" represents the leading coefficient: a = 1
(h,k) are the coordinate of the vertex of parabola.
We'll create a perfect square within the given quadratic:
f(x) = (x^2 - 14x + 49) + 1
f(x) = (x - 7)^2 + 1
The coordinates of the vertex of the parabola are (7 , 1).
The vertex form of the given quadratic f(x) = x^2 - 14x + 50 is f(x) = (x - 7)^2 + 1.