# How would you write a two column proof for the following statement?Given: m<1= m<3+m<4 Prove: m<3+m<4+m<2=180

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Assuming this is about a 4-sided polygon whose angles will sum to 360, this is impossible to prove. I will name the angles A,B,C, and D to make it easier to type.

We know that A+B+C+D = 360.

If B+C+D = 180 (this is what you're trying to prove) then A, the remaining angle, is also 180 because 180+180=360.

However, if A is 180, then C+D is also 180, based on the given.

Substituting these values into A+B+(C+D) we get 180+B+180, which is a number greater than 360, and therefore not a quadrilateral.

Is this a puzzle? There is no clarity in the question. From all the details we understand and interpret this as a question in geometry related with angles:

I reconstruct the question as follows (sorry if I differ from your intention ):

ABC is a triangle with angle A=m2 , angle B =m3 and angle C=m4. Produce AB upto D. Then Angle DBC is the exterior angle at B is m1.

It is given that m1=m3+m4.................(1)

To prove m2+m3+m4=180 deg

Add m2 to both sides of the equation at (1), then

m1**+m2**=m3+m4**+m2**............................(2)

But on the left side m1 and m2 are supplementary angle at B ,as DBC=m1 CBA=m2 and AD is the line AB extended .

Therefore, m1+m2=180 deg and so,the value on the right side of the equation at (2) ,i.e, m2+m3+m4 is equal to 180 degree.