# how would you solve -4<3x-1<5

pohnpei397 | Certified Educator

The answer to this should be

-1 < x < 2

Here is how you solve this:

Basically, you just need to treat this like a regular equation -- you isolate x and then you reduce the x term to get it, in this case, to be x and not 3x.

So, first you add 1 to all three parts of the equation.  That gives you

-3 < 3x < 6

Then you divide all sides by 3 to get the middle to be just x.

-1 < x < 2

You can check to see if this is true by putting any number into the original equation.  If you use 0 or 1, the original inequality is true.  If you use other numbers, it is not.

hala718 | Certified Educator

-4<3x-1<5 to solve this inequality we need to keep x by itself. First we add 1

==> -4+1<3x< 5+1

==> -3<3x<6...... now divide by 3

==> -3/3 < 3x/3 < 6/3

==> -1 < x < 2

then x values belong to the interval (-1,2)

neela | Student

-4<3x-1<5 To solve for x.

Solution:

There are  two inequalities.

-4>3x-1 and 3x-1<5.

-4>3x-1. Add 1 to both sides inequality does not change.

-4+1>3x. Or

-3 > 3x

Diving by postive quantity does not change the inequality. Divide by 3.

-1 < x. Or x is greater  than -1.........(1)

From the right part of the inequality,

3x-1 < 5. Add 1 to both sides.

3x < 5+1 = 6. Divide by 3 both sides;

x < 6/3 = 2. So x is less than 2..........(2)

We can combine (1) and (2) like : -1 < x < 2.