How would I solve this problem (2/3)x - (1/5) y = 10

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(2/3)x - (1/5) y = 10

to solve for x in terms of y:

(2/3)x - (1/5) y = 10

(2/3)x = 10 + (1/5)y

x = (10 + (1/5)y)(3/2)

x = 15 + 3/10 y

if y = 0; x = 15

to solve for y in terms of x:

(2/3)x - (1/5) y = 10

-(1/5) y = 10 - (2/3)x

y = (10 - (2/3)x) -5

y = -50 + 10/3 x

if x = 0; y = -50

slope = 10/3 

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