# How would I solve this problem (2/3)x - (1/5) y = 10

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(2/3)x - (1/5) y = 10

to solve for x in terms of y:

(2/3)x - (1/5) y = 10

(2/3)x = 10 + (1/5)y

x = (10 + (1/5)y)(3/2)

x = 15 + 3/10 y

**if y = 0; x = 15**

to solve for y in terms of x:

(2/3)x - (1/5) y = 10

-(1/5) y = 10 - (2/3)x

y = (10 - (2/3)x) -5

y = -50 + 10/3 x

**if x = 0; y = -50**

**slope = 10/3 **

Given: (2/3)x - (1/5) y = 10

To Find: Values of x and y

Answer:

Let us solve for x in terms of y,

(2/3)x - (1/5) y = 10

`=> (2/3) x = 10 + (1/5)y`

`=> x = (3/2) xx (10 + (1/5)y)`

`=> x = 15 + (3/10)y`

If we put y = 0 in the above equation, we get x = 15

Now let us solve for y in terms of x,

(2/3)x - (1/5) y = 10

`=> (2/3)x - 10 = (1/5) y`

`=> (1/5)y = (2/3)x - 10`

`=> y = (5/1) xx ((2/3) x - 10)`

`=> y = (10/3) x - 50`

If we put x = 0 in the above equation, we get y = -50

2/3x-1/5y=10 add 1/5 on both side

2/3x-1/5y+1/5=10+1/5y divide by 2/3 on both side

x= 15+3/10y

2/3x-1/5y=10 subtract 2/3 on both side

2/3x-1/5y-2/3x=10-2/3x divided both side by -1/5

y= -50+10/3x