You should use the absolute value property such that:
`|x|< a => -a < x < a`
You need to solve the inequality `2x-5<-1` such that:
`2x - 5<-1 => 2x < 5-1 => 2x<4 => x< 2`
`x in (-oo,2)`
You need to solve the inequality `2x-5>1` such that:
`2x-5>1 => 2x>5+1 =>2x>6 => x>3`
`x in (3,oo)`
You should intersect the intervals above such that:
`x in (-oo,2)nn(3,oo)` = `O/ `
Hence, evaluating the solution to the given inequality yields x in `(-oo,2)nn(3,oo)` = `` `O/` .
There would be multiple answers to that problem, since it is an absolute value expression.
First, you remove the absolute value signs, and make two problems.
2: 2x-5 >-1
Then you solve each problem:
The answer is in an OR format. X is greater than 3, or X is greater than 2.