How would I graph 5x+3y=-15? How would I graph 8x+2y=-4? Is the x=8/-3 the x-intercept for the equation -3x+4y=8?
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One method to graph is to find the x and y intercept of the equation. Then use the intercepts to graph the line.
Example 1: `5x+3y=-15`
To find the x-intercept of the linear equation let y=0 and solve for the x value.
`5x+3y=-15`
`5x+3(0)=-15`
`5x=-15`
x=-3
Therefore one point on the line is the coordinate (-3, 0).
To find the y=intercept of the linear equation let x=0 and solve for the y value.
`5x+3y=-15`
`5(0)+3y=-15`
`3y=-15`
`y=-5`
Therefore a second point on the line is the coordinate (0, -5).
Plot the points (-3, 0) and (0, -5) and draw a line through the two points.
The same method can be used for the second example.
Example 2: `8x+2y=-4`
To find the x-intercept of the linear equation let y=0 and solve for the x value.
`8x+2y=-4`
`8x+2(0)=-4`
`8x=-4`
`x=-1/2`
Therefore one point on the line is the coordinate (-1/2, 0).
To find the y=intercept of the linear equation let x=0 and solve for the y value.
`8x+2y=-4`
`8(0)+2y=-4`
`2y=-4`
`y=-2`
Therefore a second point on the line is the coordinate (0, -2). Plot the points (-1/2, 0) and (0, -2) and draw a line through the two points.
Example 3: `-3x+4y=8`
To find the x-intercept of the linear equation let y=0 and solve for the x value.
`-3x+4y=8 `
`-3x+4(0)=8`
`-3x=8`
`x=-8/3`
Therefore one point on the line is the coordinate (-8/3, 0). To find the y=intercept of the linear equation let x=0 and solve for the y value.
`-3x+4y=8`
`-3(0)+4y=8`
`4y=8`
`y=2`
Therefore a second point on the line is the coordinate (0, 2). Plot the points (-8/3, 0) and (0, 2) and draw a line through the two points.
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