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Since you have negatives in the middle and a positive at the end, both of your binomials will have a minus sign.
Since you have an x^3, you will have to have x in the first part of each binomial.
Look at the numbers involved: 12, 18, 8 and 12.
6 x 2 = 12 could get you both 12s and the 8, but not the 18. You need either 6 x 3 or 9 x 2 to get the 18. 9 doesn't look promising, so try 6, 2 and 3. then what do you need for the last part? 4
(6x^2 - 4) (2x - 3)
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