How to solve this problem? Use the Laplace transform to solve the given initial value problem. y'' - 2y' +2y = 0; y(0)=1, y'(0)=0
- print Print
- list Cite
Expert Answers
hala718
| Certified Educator
calendarEducator since 2008
write3,662 answers
starTop subjects are Math, Science, and Social Sciences
`y'' - 2y' + 2y = 0 `
`=> L(y''-2y'+2y) = L (0) `
`==> L{y''}(s) - 2L{y'}(s) + 2{y}(s) = 0`
Now let `y(s)= L{y}(s) `
`==gt L{y'}(s)= sy(s) - y(0)= sy(s) - 1`
` ==gt L{y''}(s)= s^2 Y(s) - sy(0) -...
(The entire section contains 130 words.)
Unlock This Answer Now
Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.
Related Questions
- How to solve this problem? Use the Laplace transform to solve the given initial value problem....
- 1 Educator Answer
- solve the initial value problem y"+y'-2y=-4; y(0) = y'(0)=0 using Laplace...
- 1 Educator Answer
- Solve y''+4y'+3y=0, y(0)=2, y'(0)=-1
- 1 Educator Answer
- How to solve the following initial value problem: `y''+8y'-9y=0, y(1)=1, y'(1)=0`I think that the...
- 1 Educator Answer
- Verify that `y = -tcos(t) - t` is a solution of the initial value problem `t(dy/dt) = y +...
- 1 Educator Answer