How to solve these logarithmic functions? 2. What is the values (if any) of the following? e^x as x--> - infinity

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You should evaluate the limit of the function `e^x`  under the given condition, such that:

`lim_(x->-oo) e^x = e^(-oo)`

Using negative power property yields:

`a^(-b) = 1/a^b`

Reasoning by analogy yields:

`e^(-oo) = 1/e^oo = 1/oo = 0`

Hence, evaluating the limit of the given function `e^x` , under the given conditionsm, yields `lim_(x->-oo) e^x = 0.`

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