If cos(A) = cos(B), then
case 1: A = n*2Pi+B, where n is an integer,
case2: A = n*2Pi-B
A = 2x+pi/2, B = x-pi/2
case 1:
2x+pi/2 = n*2pi+x-pi/2
x + pi = n*2pi
x = pi(2n-1), or x = -pi for n=0
case 2:
2x+pi/2 = n*2pi-(x-pi/2)
2x+pi/2 = n*2pi-x+pi/2
3x = n*2pi
x = 2nPi/3, or x = 0 for n=0
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