How to re-write a solution to the inequalities as an "interval" that satisfies the inequality? I need to sketch the polynomial and determine the intervals that satisfy each inequality; a....
How to re-write a solution to the inequalities as an "interval" that satisfies the inequality?
I need to sketch the polynomial and determine the intervals that satisfy each inequality;
a. 2x³+3x²-17x-30 < 0
b. 3x⁴+x³-36x²+36x+16 ≧ 0
I've already gotten the roots and my teacher wrote that "All roots are fine" but I need to write the inequality as an interval. My solution to question a. was "Polynomials as f(x) = (x-3)(2x+3)(x+2) and Solution set x = {-2.5, 2, 3}
Any help is greatly appreciated! Thank you.
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You need to sketch the graph of cubic polynomial `f(x) = 2x^3 + 3x^2 - 17x - 30` such that:
Notice that the curve intersects x axis at `x = -2.5, x = -2` and x`= 3` , hence, the...
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I think that the ansmer to problem a would be x<-2 and -2<x<3. The equation in problem b factored is (x-2)(x-2)(3x+1)(x+4), and the intervals would be x=2, -4<=x<=-1/3.
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