How to re-write a solution to the inequalities as an "interval" that satisfies the inequality? I need to sketch the polynomial and determine the intervals that satisfy each inequality; a....

How to re-write a solution to the inequalities as an "interval" that satisfies the inequality?

I need to sketch the polynomial and determine the intervals that satisfy each inequality;

a. 2x³+3x²-17x-30 < 0

b. 3x⁴+x³-36x²+36x+16 ≧ 0

I've already gotten the roots and my teacher wrote that "All roots are fine" but I need to write the inequality as an interval. My solution to question a. was "Polynomials as f(x) = (x-3)(2x+3)(x+2) and Solution set x = {-2.5, 2, 3}

Any help is greatly appreciated! Thank you.

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You need to sketch the graph of cubic polynomial `f(x) = 2x^3 + 3x^2 - 17x - 30`  such that:

 Notice that the curve intersects x axis at `x = -2.5, x = -2`  and x`= 3` , hence, the...

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waylon531 | Student

I think that the ansmer to problem a would be x<-2 and -2<x<3. The equation in problem b factored is (x-2)(x-2)(3x+1)(x+4), and the intervals would be x=2, -4<=x<=-1/3.

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