How much work does the electric field do in moving a proton from a point with a potential of +125 V to a point where it is -55.0 V? Express your answer both in joules and electron volts, please.
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quirozd
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Given: V_a = +125 V
V_b = -55.0 V
and q_p = +1e = +1.602\times10^-19\text(C)
The electric field does work on the proton much like the gravitational field does work on a mass. A mass falls from high potential to low potential, like a positive test charge in an electric field.
`\DeltaV_(ba)=-W_(ba)/q`
which becomes `W_(ba) = -\DeltaV_(ba)*q`
`-(V_b-V_a)*q = -((-55.0V)-(125V))*(1e) = 180 eV`
To get joules, we multiply by the actual charge.
`180 eV*(1.602\times10^-19\text(J)/\text(eV))`
`=2.88\times10^(-17) \text(J)`
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