How much silver is produced if 15.00 grams of Cu is added to the solution of excess silver nitrate?
If we were to add a piece of solid Cu to an aqueous solution of silver nitrate, the silver would be replaced in a single replacement reaction forming aqueous copper (II) nitrate and solid silver. How much silver is produced if 15.00 grams of Cu is added to the solution of excess silver nitrate?
Answer in the following steps:
(The balanced chemical equation is Cu+2AgNO3 ---->Cu(NO3)2+2Ag )
Step 1: Convert g Cu to moles Cu:
Step 2: Convert moles of Cu to moles of Ag produced:
Step 3: Convert moles Ag to grams of Ag produced:
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Cu + 2AgNO3 --> Cu(NO3)2 + 2Ag
If we have 15 grams of copper, we should divide it by the atomic weight of copper to get the number of moles of copper:
15 g (1 mole/63.546 g) = 0.236 moles copper
From the equation above, we can see that one mole of copper produces two moles of silver, so multiply the number of moles by 2:
0.236 moles * 2 = 0.472 moles silver
Now multiply the moles of silver by the atomic weight of silver to get the number of grams of silver produced:
0.472 moles (107.87 g/mole) = 50.91 grams silver
So 50.91 grams of silver are produced.
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