# How much heat would be required to warm oceans by 1.0 degree celcius. V of ocean water 137 x 10 ^7 km ^3 and the density of seawater is 1.03g/cm^3. Assume also heat capacity of seawater is the same as that of water. We calculate temperature change due to heat transfer with this equation:

Q = m x c x delta T

Where  Q stands for the enegry transferred, m is the mass of the material, c is the specific heat capacity of the material, and delta T is the change in temperature.

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We calculate temperature change due to heat transfer with this equation:

Q = m x c x delta T

Where  Q stands for the enegry transferred, m is the mass of the material, c is the specific heat capacity of the material, and delta T is the change in temperature.

In this case, c = 4.186 joules per gram per degree C

Delta T = 1

We need to calculate the mass of the oceans in grams for m

1 Km = 1 x 10^5 cm; we cube this to get:

1 Km^3 = 1 x 10^15 cm^3

Then we can do the conversion -

137 x 10^7  Km^3   x    1 x 10^15 cm^3/1 Km^3 =  1.37x10^24

Now, back to Q = m X c X delta T

Q = 1.37x10^24 x 4.186 x 1

Q = 5.735x10^24 Joules

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