How much heat would be required to warm oceans by 1.0 degree celcius. V of ocean water 137 x 10 ^7 km ^3 and the density of seawater is 1.03g/cm^3.
Assume also heat capacity of seawater is the same as that of water.
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We calculate temperature change due to heat transfer with this equation:
Q = m x c x delta T
Where Q stands for the enegry transferred, m is the mass of the material, c is the specific heat capacity of the material, and delta T is the change in temperature.
In this case, c = 4.186 joules per gram per degree C
Delta T = 1
We need to calculate the mass of the oceans in grams for m
1 Km = 1 x 10^5 cm; we cube this to get:
1 Km^3 = 1 x 10^15 cm^3
Then we can do the conversion -
137 x 10^7 Km^3 x 1 x 10^15 cm^3/1 Km^3 = 1.37x10^24
Now, back to Q = m X c X delta T
Q = 1.37x10^24 x 4.186 x 1
Q = 5.735x10^24 Joules
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