The solutions of `cos(pi/2*sin x) = sin(pi/2*cos x)` have to be determined.

`cos(pi/2*sin x) = sin(pi/2*cos x)`

`=> sin (pi/2 - pi/2*sin x) = sin(pi/2*cos x)`

`=> pi/2 - pi/2*sin x = pi/2*cos x` `pi/2 - pi/2*sin x = -pi/2*cos x`

`pi/2 - pi/2*sin x = pi/2*cos x`

=> `1 - sin x = cos x`

The solution of `1 - sin x - cos x = 0` can be determined by looking at the graph of the function.

The solution of `1- sin x - cos x = 0` in `[0,pi]` is `0` and `pi/2`.

The solution of the equation `cos(pi/2*sin x) = sin(pi/2*cos x)` in `[0, pi]` is `(0, pi/2)`.

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