How many moles of oxygen will be produced by 0.66 moles of potassium chlorate?

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Potassium chloride has the formula KClO3. When heated, it undergoes decomposition to produce oxygen gas according to the following equation:

`2KClO_3 -> 2KCl + 3O_2`

For each mole of potatassium chlorate that reacts one mole of oxygen gas is produced. This tells us that 0.66 moles of KClO3 will produce...

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Potassium chloride has the formula KClO3. When heated, it undergoes decomposition to produce oxygen gas according to the following equation:

`2KClO_3 -> 2KCl + 3O_2`

For each mole of potatassium chlorate that reacts one mole of oxygen gas is produced. This tells us that 0.66 moles of KClO3 will produce 0.99 moles of O2:

0.66 moles KClO3 x (3 mole O2/2 mole KClO3) = 0.99 moles O2

The moles of a given quantity is multipled by the mole ratio of unknown to given, which is the ratio of coefficients from the balanced equation. In this case the coefficients are 2 and 3. 

Potassium chlorate can cause other substances to spontaneously combust, especially if it's heated. The oxygen produced creates a more flammable environment than the atmosphere alone, which is about 20% oxygen.

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