How many moles of H2SO4 will react with 18 mol of Al in a chemical reaction involving the two.

Expert Answers

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Aluminum reacts with `H_2SO_4` to form `Al_2(SO_4)_3` . The equation of the chemical reaction is:

`2Al + 3H_2SO_4 -> Al_2(SO_4)_3 + 3H_2 `

2 moles of aluminum react with 3 moles of hydrogen sulfide. 18 moles of Al will react with (18/2)*3 = 27 moles of hydrogen sulfide.

18 moles of aluminum react with 27 moles of hydrogen sulfide in the reaction involving the two.

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First we will need to the complete chemical reaction involving sulfuric acid and alluminium.

2Al + 3H2SO4 -----> Al2(SO4)3 + 3H2

From the reaction 

2 moles of Al react with 3 moles of H2SO4 [ That is is 2:3 ratio]

So

18 moles of Al will react with 27 moles of H2SO4.

SOLUTION:-

(18 * 3)/2  = 27 moles of H2SO4.

Therefore 18 moles of Al will require 27 moles of H2SO4 to react.

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