How many liters of 3.4 M solution can be made using 78 grams of isopropanol (C3H8O)?

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A solution with a concentration of 1 M has one mole of the solute in every liter of the solution.

If a solution has a molarity of 3.4 M, it has 3.4 moles of the solute in every liter of the solution. A 3.4 M solution of isopropanol has 3.4...

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A solution with a concentration of 1 M has one mole of the solute in every liter of the solution.

If a solution has a molarity of 3.4 M, it has 3.4 moles of the solute in every liter of the solution. A 3.4 M solution of isopropanol has 3.4 moles of isopropanol per liter of the solution. The molecular mass of isopropanol is 60 g/ mole.

78 grams of isopropanol is 78/60 = 1.3 mole.

Using 1.3 mole of isopropanol it is possible to make 1.3/3.4 = 0.3823 liters of the solution.

The number of liters of 3.4 M solution of isopropanol that can be made using 78 grams of isopropanol is 0.3823 liters.

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