A solution with a molar concentration or molarity of 0.7 M has 0.7 moles of the solute per liter of the solution. Here, we need to create a solution of lead (II) oxide with a molarity of 0.7 M. The amount of lead (II) oxide we have is 75 grams.

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A solution with a molar concentration or molarity of 0.7 M has 0.7 moles of the solute per liter of the solution. Here, we need to create a solution of lead (II) oxide with a molarity of 0.7 M. The amount of lead (II) oxide we have is 75 grams.

As the molar mass of lead(II) oxide is 223.20 g/mole, 75 grams is equal to 75/223.2 = 0.3360 moles. For each liter of the solution we need 0.7 moles. With 0.3360 moles we can make 0.3360/0.7 = 0.48 L of the solution.

The number of liters of the solution of lead (II) oxide with a molar concentration of 0.7 that can be made with 75 g of lead(II) oxide is 0.48 L.