To solve for the amount of Iron (Fe) that can be recovered from iron ore (Fe2O3), we will apply stoichiometry procedures.

We can also look at the relationship of Fe with Fe2O3. In one mole of Fe2O3, there are two moles of Fe atoms.

First, convert the mass of ore...

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To solve for the amount of Iron (Fe) that can be recovered from iron ore (Fe2O3), we will apply stoichiometry procedures.

We can also look at the relationship of Fe with Fe2O3. In one mole of Fe2O3, there are two moles of Fe atoms.

First, convert the mass of ore in grams. We know that 1000 grams = 1kg, therefore 639 kilograms is equal to 639,000 grams.

`639,000 grams Fe2O3 * ((1 mol e Fe2O3)/( 159.69 grams Fe2O3)) * ((2 mol es Fe)/(1 mol e Fe2O3)) * ((55.85 grams Fe)/(1 mol e Fe)) `

`= 446,968 grams Fe `

Finally, convert back the mass of Fe in grams to kilograms.

**447 kilograms of Fe can be recovered.**