How many grams of Zn will be produced from 3.00 mol of Ca in the following reaction: Ca + ZnCO3 → CaCO3 + Zn
First balance the given reaction.
This reaction is balanced
Ca + ZnCO3---> CaCO3 + Zn.
Given is 3 moles of Ca.
So now we have to find that how many moles of Zn is formed when 3 moles of Ca is reacting.
From the reaction we can see that they are in the 1:1 ratio that means one mole of Ca give rise to one mole of Zn.
So 3 moles of Ca will give rise to 3 moles of Zn.
Now we are asked to find the mass.
We got 3 moles of Zn.
Moles = mass / molar mass.
Mass = Moles * Molar Mass
Mass = 3 mole * 65.39 gm/mole
Mass = 196.17 gm.
Therefore when 3 mole of Ca is reacting 196.17 gm of Zn is formed.
The reaction between calcium and zinc carbonate leads to the formation of calcium carbonate and zinc. The chemical equation of the reaction is:
Ca + ZnCO3 --> CaCO3 + Zn
In the reaction one mole of Ca reacts with one mole of ZnCO3 to give one mole of CaCO3 and one mole of Zn. 3 moles of Ca will yield 3 moles of Zn. The molar mass of zinc is 65.38. 3 moles of zinc have a mass of 196.14 g.
When 3 moles of Ca take part in the reaction represented by: Ca + ZnCO3 --> CaCO3 + Zn, 196.14 g of zinc is produced.