how many grams of oxygen are there in 26.2 grams of mg(oh)2?

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jerichorayel | College Teacher | (Level 2) Senior Educator

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You can solve for the grams of oxygen by getting the molecular masses of O and Mg(OH)2. We can apply mass balance to solve the answer.

There are 2 molecules O in 1 molecule of Mg(OH)2.

`26.2 grams Mg(OH)2 * ((2 * Molar mass O)/(Molar mass Mg(OH)2))`

`26.2 grams Mg(OH)2 * ((2 * (16(g O)/(mol)))/(58.32 (g Mg(OH)2)/(mol)))`

`26.2 * ((32)/(58.32)) `

Mass of O = 14.266 = 14.3 grams of Oxygen are present in 26.2 grams of Mg(OH)2 sample.

 

 

 

 

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