How many grams of carbon dioxide would be required to form 332.31 grams of glucose, assuming abundant water was available?

Expert Answers

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The chemical reaction that converts carbon dioxide and water to glucose can be written as:

`6CO_2 + 6H_2O -> C_6H_12O_6 + 6O_2`

Here, 6 moles of carbon dioxide reacts with 6 moles of water and forms 1 mole o glucose and 6 moles of oxygen. 

Molar mass of glucose is 180 g/mol (= 6 x 12 + 12 x 1 + 6 x 16) and carbon dioxide is 44 g/mol (= 12 + 2 x 16).

Hence, from stoichiometry,

1 mole of glucose requires 6 moles of carbon dioxide

or, 180 g of glucose requires 6 x 44 = 264 g carbon dioxide

or, 1 g glucose requires 264/180 g carbon dioxide

or, 332.31 g glucose requires (264/180) x 332.31 = 487.39 g carbon dioxide.

Thus, 487.39 g carbon dioxide is needed to produce 332.31 g glucose.

Hope this helps.

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