How many grams of aluminum sulfate Al2(SO4)3 , will be produced from the complete reaction of 270g of Al

Expert Answers

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`2Al_((s))+3H_2SO_(4(aq)) rarr Al_2(SO_4)_(3(aq))+3H_(2(g))`

`Al_2(SO_4)_3` is formed when we add `H_2SO_4` acid to Al solid.

Mole ratio

`Al:Al_2(SO_4)_3 = 2:1`

Molar mass of Al = 27g/mol

Amount of Al reacted `= 270/27 = 10mol`

Amount of `Al_2(SO_4)_3` formed `= 1/2xx10 = 5mol`

Molar mass of `Al_2(SO_4)_3` = 342g/mol

Mass of `Al_2(SO_4)_3` obtained `= 342xx5 = 1710g`

So we can get a maximum of 1710g of `Al_2(SO_4)_3` .


  • There is enough Sulphuric acid for the complete reaction
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