How many grams of aluminum sulfate Al2(SO4)3 , will be produced from the complete reaction of 270g of Al

Expert Answers

An illustration of the letter 'A' in a speech bubbles

`2Al_((s))+3H_2SO_(4(aq)) rarr Al_2(SO_4)_(3(aq))+3H_(2(g))`

`Al_2(SO_4)_3` is formed when we add `H_2SO_4` acid to Al solid.

Mole ratio

`Al:Al_2(SO_4)_3 = 2:1`

Molar mass of Al = 27g/mol

Amount of Al reacted `= 270/27 = 10mol`

Amount of `Al_2(SO_4)_3` formed `= 1/2xx10 = 5mol`

Molar mass of `Al_2(SO_4)_3` = 342g/mol

Mass of `Al_2(SO_4)_3` obtained `= 342xx5 = 1710g`

So we can get a maximum of 1710g of `Al_2(SO_4)_3` .

Assumption

  • There is enough Sulphuric acid for the complete reaction
Approved by eNotes Editorial Team

We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

  • 30,000+ book summaries
  • 20% study tools discount
  • Ad-free content
  • PDF downloads
  • 300,000+ answers
  • 5-star customer support
Start your 48-Hour Free Trial