The distance between A and B is 900 km. How long does it take to go from A to B if a person walks: A) 5 km/h without stopping? B) 5 km/h for 10h each day? C) 1.5 m/s without stopping?
Average speed is the total distance traveled divided by the total time taken. Speed = distance/time or time = distance /speed.
The distance from A to B is 900 km.
If a person walks from A to B at 5 km/h without stopping, the time taken to cover the distance is 900/5 = 180 hours.
If a person walks at 5 km/h for 10 h each day, the number of days required to cover the distance is 900/50 = 18 days.
If a person walks at 1.5 m/s without stopping the time taken to cover the distance is 900*1000/1.5 = 600000 seconds.
Since you've not provided anything about the direction of moving, but the average speed, we can determine the time of travel:
We'll recall the formula that gives the time when we know the distance and the average speed:
total time = total distance walked/v av.
total time = 900Km/5Km/h
total time = 180 hours
If the person walks 5Km/h, 10h/day, we'll get:
We'll apply the rule of 3, to get the number of km traveled in 10 hours.
x = 5*10 = 50Km
The person walks from A to B within 900/50 = 18 days.
To determine the time of travel if the average speed is of 1.5m/s, we'll convert the 900Km into meters => 900Km = 900*1000= 9*10^5 m
total time = 9*10^5 m/1.5 m/s
total time = 9*10^6/15
total time = 3*10^6/5
total time = 6*10^5 s