Question

How to find x and y intercepts for the equation 2x+3y-15=0?

Accepted Answer

The x-intercept has a y-value of 0 and the y-intercept has an x-value of 0.  Therefore, you can find the x and y intercepts by substituting 0 in for each variable one at a time.
x-intercept:
2x + 3(0) - 15 = 0
2x - 15 = 0
2x = 15
x = 7.5
The x-intercept is (7.5, 0).
 
y-intercept:
2(0) + 3y - 15 = 0
3y - 15 = 0
3y = 15
y = 5
The y-intercept is (0, 5).
 
You can check this answer by graphing the line.
Rewrite the equation as y = (-2x + 15) / 3

The line intersects the x-axis at 7.5 and the y-axis at 5.

Answer

The equation of a straight line in intercept-intercept form is x/a+y/b = 1 where a is the x-intercept and b is the y-intercept.
Convert the standard form of the equation of the line into the intercept-intercept form.
2x+3y-15=0
Add 15 to both the sides
2x+3y= 15
Divide both sides by 15
(2x)/15 + (3y)/15 = 1
x/(15/2) + y/(15/3) = 1
x/7.5 + y/5 = 1
The x-intercept of the line is 7.5 and the y-intercept is 5

Answer

To determine x axis intercept of the given line, we'll have to set y = 0.
2x + 3*0 - 15 = 0
2x - 15 = 0
x = 15/2
The x axis intercepting point is (15/2 ; 0).
To determine y axis intercept of the given line, we'll have to set x = 0.
2*0 + 3y - 15 = 0
3y - 15 = 0
3y = 15
y = 15/3
y = 5
The y axis intercepting point is (0 ; 5).
Therefore, the x and y axis intercepts are: (15/2 ; 0) and (0 ; 5).

Math

How to find x and y intercepts for the equation 2x+3y-15=0?

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